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CBSE Class 10 Answered

oemetricaly derive the value of sin 30
Asked by amolshukal.2001 | 31 Jan, 2018, 08:47: AM
answered-by-expert Expert Answer
 
 
begin mathsize 16px style Consider space increment ABC space is space an space equilateral space triangle space with space side space 2 straight x. Each space angle space is space 60 degree. space Let space AD perpendicular BC. AD space is space perpendicular space bisector space of space BC. BD equals DC equals fraction numerator 2 straight x over denominator 2 end fraction equals straight x angle BAD equals 30 degree In space increment ADB comma AD squared plus BD squared equals AB squared AD squared plus straight x squared equals open parentheses 2 straight x close parentheses squared AD squared equals 4 straight x squared minus straight x squared AD squared equals 3 straight x squared AD equals square root of 3 straight x BD equals straight x space and space AB equals 2 straight x space and space angle DAB equals 30 degree sin 30 degree equals BD over AB equals fraction numerator straight x over denominator 2 straight x end fraction equals 1 half Similarly space you space can space find space other space ratios space of space 30 degree space as space well space as space ratios space of space 60 degree. end style
Answered by Sneha shidid | 31 Jan, 2018, 09:14: AM

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