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O is the point of intersection of the diagonals AC and BD of a trapezium ABCD with AB  DC. Through O, a line segment PQ is drawn parallel to AB meeting AD in P and BC in Q. Prove that PO = QO.

Asked by Vivek Menon 17th September 2013, 9:52 PM
Answered by Expert
Answer:
Answered by Expert 18th September 2013, 9:16 AM
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