CBSE Class 12-science Answered
numerical!
Asked by | 29 Feb, 2008, 11:30: PM
Expert Answer
Heptance and octane form an ideal solution at 373 K, The vapour pressures of the pure liquids at this terperature
are 105.2 KPa and 46.8 KPa respectively. If the solution contains 25g of heptance and 28.5g of octane, calculate
(i) vapour pressure exerted by heptane
(ii) vapour pressure exerted by solution
(iii) mole fraction of octane in the vapour phase
apply raoults law p1=105.2 X mole fraction of heptane
p2 = 46.8 X mole fraction of octane
v.pr solution= p1 +p2
Answered by | 02 Mar, 2008, 06:43: PM
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