MID PTS THEOREM
in the triangles FHC and HEB
EB=FC....since they are half parts of equal sides AB ,CD.
FC II EB
angle FCH= angle HEB
angle CFH= angle HBE...(alt interior angles)
so triangles are cong by ASA rule.
consider the quadrilaterlal AECF,
AE=CF....half parts of equal sides AB and CD
AE II CF...since AB , CD are parallel.
so AECF is a parallelogram.
GF II EH
GE II HF
so GEHF is also a parallelogram... both pairs of opp sides are parallel.
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