CBSE Class 9 Answered
MID PTS THEOREM
Asked by | 13 Sep, 2009, 06:44: AM
Expert Answer
let ABCD be a parallelogram.
E,F,G,H be the mid points of the sides AB,BC,CD,DA.
join BD.
EH II BD...
and
EH =1/2[BD]....mid pt thm
Simly
FG II BD and FG=1/2[BD]
So EH=FG
and
EH II FG
So
EFGH is a parallelogram....one pair of opp sides is parallel and equal
so FH and EG become the diagonals of this parallelogram, so they must bisect each other.
Answered by | 13 Sep, 2009, 08:46: AM
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