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MID PTS THEOREM

Asked by 13th September 2009, 6:44 AM
Answered by Expert
Answer:

let ABCD be a parallelogram.

E,F,G,H be the mid points of the sides AB,BC,CD,DA.

join BD.

EH   II BD...

and

EH =1/2[BD]....mid pt thm

Simly

FG II BD and FG=1/2[BD]

So EH=FG

and

EH II FG

So

EFGH is a parallelogram....one  pair of opp sides is  parallel and equal

so FH and EG become the diagonals of this parallelogram, so they must bisect each other.

Answered by Expert 13th September 2009, 8:46 AM
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