CBSE - IX - Mathematics - Lines and Angles
MID PTS THEOREM
let ABCD be a parallelogram.
E,F,G,H be the mid points of the sides AB,BC,CD,DA.
EH II BD...
EH =1/2[BD]....mid pt thm
FG II BD and FG=1/2[BD]
EH II FG
EFGH is a parallelogram....one pair of opp sides is parallel and equal
so FH and EG become the diagonals of this parallelogram, so they must bisect each other.
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