Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

Light of wavelength L falls on a metal surface with intensity X and the metal emits Y electrons per second of average energy Z. what happens to Y and Z if L is halved????

Asked by MAANASI.M 6th October 2013, 5:52 PM
Answered by Expert
Answer:

For a given metal, the number of electrons ejected per second is directly proportional to the intensity of the incident light. Since there is no change in the intensity hence, Y will not change on changing L.

Above the threshold frequency, the maximum kinetic energy of emitted electrons is independent of the intensity of the incident light but depends only on the frequency (or wavelength) of the incident light.

Wavelength (L) is halved means that the frequency is doubled since frequency is inversely proportional to wavelength. Hence, the energy of emitted electrons will become twice since it depends upon the frequency of incident light.

Answered by Expert 15th October 2013, 2:46 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp