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let ABC be a triangle with position vectors of its erties as 7j+10k,-i+6j+6k and -i+4j+6k.Then AB is a 

Asked by g_archanasharma 15th April 2019, 6:07 PM
Answered by Expert
Answer:
straight a equals space 7 straight j plus 10 straight k
straight b equals negative straight i plus 6 straight j plus 6 straight k
straight c equals negative straight i plus 4 straight j plus 6 straight k
AB equals open parentheses straight b minus straight a close parentheses equals negative straight i plus 6 straight j plus 6 straight k minus open parentheses 7 straight j plus 10 straight k close parentheses
equals negative straight i minus straight j minus 4 straight k
Answered by Expert 16th April 2019, 10:16 AM
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