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Let a right triangle BAC in which ∠A is right angle and AC = y, AB = x. Three equilateral triangles ΔAEC, Δ AFB and ΔCBD are drawn on the three sides of ΔABC. Again let area of triangles made on AC, AS and BC are A1, A2 and A3, respectively. To prove A3 = A1 + A2
Asked by rushabhjain.avv | 24 Aug, 2018, 12:04: AM
answered-by-expert Expert Answer
begin mathsize 18px style space AC space equals space straight y comma space AB space equals space straight x. BC space equals square root of straight x squared plus straight y squared end root..... pythagoras straight A subscript 1 equals fraction numerator square root of 3 over denominator 4 end fraction straight y squared straight A subscript 2 equals fraction numerator square root of 3 over denominator 4 end fraction straight x squared straight A subscript 3 equals fraction numerator square root of 3 over denominator 4 end fraction open parentheses straight x squared plus straight y squared close parentheses equals straight A subscript 1 space plus space straight A subscript 2 end style
Answered by Arun | 27 Aug, 2018, 11:06: AM

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