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kindly solve (ref. 522)

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Asked by arup.isro 12th July 2018, 11:12 PM
Answered by Expert
Answer:
Figure shows how the normal forces are acting on bottom bars.
Triangle formed by connecting the 3 centers of circle is equilateral triangle.
 
From forces acting on vertical direction, we have 2×N×cos30 = w or begin mathsize 12px style N space equals space fraction numerator W over denominator 2 space cos 30 space end fraction space equals space fraction numerator W over denominator square root of 3 end fraction end style
F = N sin30 begin mathsize 12px style equals fraction numerator W over denominator 2 square root of 3 end fraction end style
Answered by Expert 13th July 2018, 5:34 PM
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