CBSE Class 11-science Answered
Kindly answer.
Asked by Kchawla94 | 03 Mar, 2019, 09:22: PM
Expert Answer
Given sequence : M1 , M2, M3, M4, M5, M6 and M7
Each term is succeeding term minus constant d . M1 = M2 - d or M2 = M1+d ; Similarly M3 = M2 +d and so on
Hence the given sequence is Arithmetic progression with first term M1 and common difference d
M2 + M4 + M6 = M1+d + M1+3d + M1+5d = 3×M1 + 9d = 48 or M1 = 16-3d ....................(1)
M1 + M3+ M5+ M7 = = M1 + M1+2d + M1+4d +M1+6d = 4M1+12d = 4×(16-3d)+12d = 64
Answered by Thiyagarajan K | 04 Mar, 2019, 10:52: AM
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