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Kepler's third law states that square of period of revolution (T) of a planet around the sun, is proportional to third power of average distance r between sun and planet i.e. T square=K*(r)cube

Here K is constant 

If the masses of sun and planet are M and m respectively then as per Newton's law of gravitation force of attraction between them is F GMm/r square, here G is gravitational constant

The relation between G and K is described as

Asked by keshavanburajan 18th October 2018, 8:26 AM
Answered by Expert
Answer:
When the planet revolving around the sun in an elliptical orbit, centripetal force is provided by gravitational attractive force.
 
Hence begin mathsize 12px style fraction numerator G cross times M cross times m over denominator R squared end fraction space equals space m cross times omega squared cross times R space................... left parenthesis 1 right parenthesis end style
where G is gravitational constant, M is mass of sun, m is mass of planet, R is the mean distance between planet and sun
and ω is the angular speed.
 
Let T be the time period of revolution. If we substitute ω = 2π/T in eqn.(1) and rearrange the terns we get,
 
begin mathsize 12px style T squared equals fraction numerator 4 pi squared over denominator G M end fraction R cubed space equals space K cross times R cubed space...................... left parenthesis 2 right parenthesis end style
Hence we get begin mathsize 12px style K space equals space fraction numerator 4 pi squared over denominator G M end fraction end style .................................(3)
Answered by Expert 18th October 2018, 10:15 AM
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Tags: keplers-laws
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