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Is there any real value of a for which the equation-x2 +2x+(a2+1)=0 has real roots?

Asked by 5th October 2013, 3:39 PM
Answered by Expert
Answer:
A quadratic equation has two real roots if discriminant ? 0
For the given equation, we have:
D = b^2 - 4ac
   = (2)2 - 4(1)(a2 + 1)
   = 4 - 4(a2 + 1)
   = 4(1 - a2 - 1)
   = -4a2
Now, D = 0 when a = 0. So, the equation will have real and equal roots if a = 0. And for all other values of a, the equation will have no real roots.
Answered by Expert 5th October 2013, 11:21 PM
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