Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

Is molicular orbital theory is also applicable for ionic bonds?
What is the meaning of the statements "A destructive or out of phase combiation of the two atomic orbitals leads to a deacreased or zero elecron density between nuclei. This imparts instability to the molicule" & "Antibonding molicular orbital the charge density between the two nuclei is less than the sum of the charge densities of the two isolated atoms"
Asked by Vineeth K | 07 Jan, 2015, 09:23: PM
answered-by-expert Expert Answer
Dear k.vineeth26@gmail.com

Thanks for asking us a question in Ask the Expert section of TopperLearning.com.

Molecular orbital theory can give us information about both ionic and covalent molecules and naturally predicts which molecules will be ionic and which will be covalent.

 

When two atomic orbitals overlap, they can be in phase (added) or out of phase (subtracted). When they overlap in phase, constructive inter-action occurs in the region between the nuclei, and a bonding orbital is produced. The energy of the bonding orbital is always lower (more stable) than the energies of the combining orbitals. When they overlap out of phase, destructive interaction reduces the probability of finding electrons in the region between the nuclei, and an antibonding orbital is produced. This is higher in energy (less stable) than the original atomic orbitals. The overlap of two atomic orbitals always produces two MOs: one bonding and one anti-bonding.

 

 

In a bonding molecular orbital, the electron density is high between the two atoms, where it stabilizes the arrangement by exerting a strong attraction for both nuclei. By contrast, an anti-bonding orbital has a node (a region of zero electron density) between the nuclei; this allows for a strong net repulsion between the nuclei, which makes the arrangement less stable. Electrons are more stable (have lower energy) in bonding molecular orbitals than in the individual atoms. Placing electrons in antibonding orbitals, on the other hand, requires an increase in their energy, which makes them less stable than in the individual atoms.



Regards

Topperlearning Team.
Answered by Arvind Diwale | 08 Jan, 2015, 01:28: PM
CBSE 11-science - Chemistry
Asked by thesouro007 | 20 Mar, 2024, 06:05: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by shabnamaijaz83 | 19 Jun, 2022, 10:08: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by abnarsale | 31 Dec, 2021, 10:41: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by mandriosa67 | 13 Feb, 2020, 03:03: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by Shrivatsa | 25 Aug, 2019, 02:11: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by sonkarshiva009 | 13 Mar, 2019, 05:47: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by vermaarti729 | 28 Feb, 2019, 08:28: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×