CBSE Class 11-science Answered
instantaneous position of a partical at time t,is given by x=10+12t+8t square where x and t are in metre and second respectively find the
(a) initial velocity of a partical
(b)velocity of a partical at t=3sec
(c)instantaneious accerlation of partical
(d)position of particalat t=5sec
Asked by puneetgarg2555 | 15 Jun, 2018, 07:20: PM
Expert Answer
Position x(t) = 10 + 12 t + 8 t2
velocity v(t) = dx/dt = 12 + 16 t
Initial velocity, v0 at t=0, v0 = 12+16×0 = 12 m/s
velocity at t=3, v = 12+16×3 = 60 m/s
acceleration = dv/dt = 12 m/s2
position at t = 5, x(5) = 10 + 12×5 + 8×5×5 = 270 m
Answered by Thiyagarajan K | 18 Jun, 2018, 02:27: PM
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