CBSE Class 10 Answered
In triangle ABCis Equilateral and point P and Q trisect BC. Then Prove angle PAQ is 20.
Asked by Devkumar.dk554 | 10 Feb, 2019, 09:36: AM
Expert Answer
Figure shows an equilateral triangle ABC. Side BC is trisected at P and Q.
Let us join AP and AQ. let us assume, by symmetry, 
BAP = PAQ =QAC = x
BAP = PAQ =QAC = xthen APQ = AQP = 90 -(x/2)
APQ = AQP = 90 -(x/2)then APB = 90+(x/2)
APB = 90+(x/2)In ΔBAP, B + BAP +BPA = 60 + x + 90+(x/2) = 180 or (3/2)x = 30 or x = 20
B + BAP +BPA = 60 + x + 90+(x/2) = 180 or (3/2)x = 30 or x = 20Hence PAQ = 20°
PAQ = 20°
Answered by Thiyagarajan K | 11 Feb, 2019, 11:13: PM
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