CBSE Class 11-science Answered
In the graphic seen, find the (a) Speed of trolley with respect to person (2) (b) Speed of person (1) with respect to person (2).
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
(a)
We want to find Vt2= velocity of trolley with respect to person 2.
the velocity of the trolley with respect to the ground, Vtg=20m/s
We want to find Vt2= velocity of trolley with respect to person 2.
the velocity of the trolley with respect to the ground, Vtg=20m/s
And the velocity of person 2 with respect to ground V2g=-2m/s.
Also, since Vab= - Vba, we know that Vg2= +2m/s.
Also, since Vab= - Vba, we know that Vg2= +2m/s.
Using our formula, we have:
Vt2 = Vtg+ Vg2 = 20 m/s + 2m/s = 22 m/s.
(b)
We want to find
V12=V1g+Vg2.
Vg2 = 2m/s we know V1t = -5m/s, and
V12=V1g+Vg2.
Vg2 = 2m/s we know V1t = -5m/s, and
Vtg = +20 m/s.
Therefore V1t + Vtg=15m/s=V1g
Therefore V1t + Vtg=15m/s=V1g
So, V12= 15 m/s + 2 m/s = 17 m/s towards right.
Answered by | 04 Jun, 2014, 03:23: PM
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