CBSE Class 9 Answered
In the figure, PQ is a diameter of the
circle and XY is chord equal to the radius of the circle. PX and QY when
extended intersect at point E. Prove that PEQ = 60o
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
PQ is the diameter of the circle, chord XY = r (radius of circle)
PX and QY extended intersect at a point E.
To prove PEQ = 60o
XY = OX = OY [radii of a circle, Given]
XOY is an equilateral triangle
XQY = 30o [Inscribed angle is half of the central angle]
PXQ = 90o [Angle in a semi circle]
QXE = 180o - PXQ = 900 [Linear pair]
In XEQ,
XEQ = 180o - (EXQ + EQX) (Angle sum property)
XEQ = 180o - (900 + 300) = 600
PEQ = 60o
Answered by | 04 Jun, 2014, 03:23: PM
Concept Videos
CBSE 9 - Maths
Asked by geetaradha8835 | 16 Dec, 2022, 07:59: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by sangeetabharti123456789 | 22 Feb, 2022, 09:01: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by Samidhaindulkar133 | 11 Mar, 2021, 04:03: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by harjot.arshleen | 03 Feb, 2021, 02:42: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by lata15121995joshi | 03 Jan, 2020, 07:59: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by Anubhavjain599 | 26 Nov, 2019, 05:53: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by yogeshthakur3300 | 28 Dec, 2018, 08:24: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT