In the figure, ABCD is a trapezium in which AB||DC. Prove that ar(AOD) = ar(BOC).
ar(ADC) = ar(BCD)
[Triangles on the same base and between the same set of parallel lines have equal area]
Subtracting ar(DOC) from both sides, we get,
ar(ADC) - ar(DOC) = ar(BCD) - ar(DOC)
ar(AOD) = ar(BOC)
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