CBSE Class 9 Answered
In the figure, ABCD is a parallelogram. The
circle through A, B and C intersects CD produced at E. Prove that AE = AD.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
1 = 2 (Opp. angles of a parallelogram are equal)…(i)
1 + AED = 180o (Opp. Angles of cyclic Quad.)…(ii)
2 + ADE = 180o (Linear pair)…….(iii)
AED = ADE….from (i),(ii),(iii).
AD = AE (in ADE, lines opp. to equal angles are equal)
Answered by | 04 Jun, 2014, 03:23: PM
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