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In the expansion of (2x^2-8) ​​​​​​​(x-4)^2 ;find the value of : i -cofficient of x^3, ii- cofficient of x^3 and constant term.

Asked by screen1974 12th June 2019, 8:46 PM
Answered by Expert
Answer:
left parenthesis 2 x squared minus 8 right parenthesis left parenthesis x minus 4 right parenthesis squared
2 left parenthesis x squared minus 4 right parenthesis left parenthesis x minus 4 right parenthesis squared
equals 2 left parenthesis x squared minus 4 right parenthesis left parenthesis x squared minus 8 x plus 16 right parenthesis
equals 2 left parenthesis x to the power of 4 minus 8 x cubed plus 16 x squared minus 4 x squared plus 32 x minus 64 right parenthesis
C o e f f i c i e n t space o f space x cubed space equals space minus 16
C o n tan t space t e r m space i s space minus 128
Answered by Expert 13th June 2019, 10:27 AM
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