ICSE Class 9 Answered
In the expansion of (2x^2 - 8) (x - 4)^2 ; find the value of: (1) coefficient of x^3 (2)coefficient of x^2 (3)constant term
Asked by nishabr7 | 17 Jul, 2018, 05:58: PM
Expert Answer
(2x2 - 8) (x - 4)2 = (2x2 - 8)(x2 - 8x + 16)
= 2x4 - 16x3 + 32x2 - 8x2 + 64x - 128
= 2x4 - 16x3 + 24x2 + 64x - 128
Coefficient of x3 is -16
Coefficient of x2 is 24
Constsnt term is - 128
Answered by Sneha shidid | 18 Jul, 2018, 11:07: AM
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