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In the arrangement shown mass of A=1kg,mass ofB= 2kg and coefficient of friction bet A and B is 0.2.There is no friction bet B and ground.The frictional force on A is

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Asked by m.nilu 16th August 2018, 8:18 PM
Answered by Expert
Answer:
 
Normal reaction force N acting on A = 1×g = g Newton
Hence the friction force, as shown in figure = μN = 0.2×9.8 = 19.6 Newton
Answered by Expert 16th August 2018, 9:51 PM
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