In the arrangement shown mass of A=1kg,mass ofB= 2kg and coefficient of friction bet A and B is 0.2.There is no friction bet B and ground.The frictional force on A is
Asked by m.nilu
16th August 2018,
8:18 PM
Answered by Expert
Answer:
Normal reaction force N acting on A = 1×g = g Newton
Hence the friction force, as shown in figure = μN = 0.2×9.8 = 19.6 Newton
Answered by Expert
16th August 2018,
9:51 PM
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