CBSE Class 9 Answered
In the adjoining figure abcd is a square and triangle edc is an equilateral triangle .prove that 1.ae=be 2.angle dae 15°
Asked by Chaterjee.antara | 18 Mar, 2019, 12:37: PM
Expert Answer
As shown in figure, an equilateral triangle is drawn on square.
ΔADE and ΔBCE are congruent due to following reasons
AD = BC, DE = CE and ADE = BCE = (90+60)° = 150°
Hence AE = BE
ΔADE is isoceless triangle, because AD = DE
Hence DAE = DEA
since ADE = 150° , DAE = (180-150)/2 = 15°
Answered by Thiyagarajan K | 18 Mar, 2019, 01:38: PM
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