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In quest which I had asked earlier that "how many grams of urea should be added in 500 g of water for depression in freezing point of 0.2 Kelvin  Kf is 3.2" you gave the solution with which I am satisfied  But  I want to ask that when solvent here is water and its Kf is 1.86 then why 3.2 has been used as molal depression constant over here?
Asked by charvipareek057 | 17 Apr, 2019, 02:30: PM
answered-by-expert Expert Answer
K subscript f space i s space a l s o space c a l l e d space a s space bold italic C bold italic R bold italic O bold italic Y bold italic O bold italic S bold italic C bold italic O bold italic P bold italic I bold italic C bold thin space bold italic C bold italic O bold italic N bold italic S bold italic T bold italic A bold italic N bold italic T space w h i c h space i s space d e p e n d e n t space o n space T subscript m space left parenthesis F u s i o n space t e m p e r a t u r e comma space a s space p e r space t h e space r e l a t i o n minus K subscript f space equals space fraction numerator M subscript w R T squared subscript m over denominator increment H subscript f u s end subscript end fraction space t h e space v a l u e space o b t a i n e d space i s space 1.86 K K g m o l to the power of negative 1 end exponent space w h e n space R space equals space 8.314 J m o l to the power of negative 1 end exponent K to the power of negative 1 end exponent comma space T subscript m equals space 273.15 K space a n d space increment H subscript f u s end subscript space equals space 6 K J m o l to the power of negative 1 end exponent K subscript f space v a l u e space f a l l s space f r o m space t h e space a b o v e space o b t a i n e d space v a l u e space w i t h space d e c r e a s e space i n space t e m p e r a t u r e space b y space e v e r y space 10 to the power of 0 C space a n d space I n c r e a s e s space w i t h space e v e r y space 10 to the power of 0 C space r i s e. S i n c e space h e r e space d e p r e s s i o n space i n space f r e e z i n g space p o i n t space w a s space 0.2 K space s o comma space c a l c u l a t e d space v a l u e space u sin g space a b o v e space e q u a t i o n space h a d space a space v a l u e space o f space K subscript f space equals space 3.2 left parenthesis T subscript m space equals space 273.15 space plus 0.2 space equals 273.35 right parenthesis
Answered by Sumit Chakrapani | 18 Apr, 2019, 12:11: AM

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