Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 9 Answered

In figure, PQ PS, PQ||SR, SQR = 25o and QRT = 65o. Find the value of x and y.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer

QSR + SQR = QRT

(exterior angle property)

QSR = 65o - 25o = 40o

PSR + SPQ = 180o

(PQ||SR, Co-interior angles are supplementary)

PSR = 180o - 90o = 90o

PSR = y + QSR

y = 90 o - 40 o = 50o

Also x = QSR (PQ||SR, alternate interior angles are equal)

x = 40o

Answered by | 04 Jun, 2014, 03:23: PM

Concept Videos

CBSE 9 - Maths
Q1
question image
Asked by chanishant6 | 09 Sep, 2020, 11:53: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by pranita.krmis | 02 Jul, 2020, 06:20: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by pranita.krmis | 29 Jun, 2020, 02:01: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by pranita.krmis | 19 Jun, 2020, 01:51: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by pranita.krmis | 17 Jun, 2020, 06:10: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by Ravindrachavan292 | 08 Jul, 2019, 08:35: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by Girishdhawan | 01 Jul, 2018, 03:19: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×