CBSE Class 9 Answered
In figure, AB and CD are respectively the smallest and the longest sides of a quadrilateral ABCD, then show that A > C and B > D.
Asked by Topperlearning User | 11 Aug, 2017, 09:09: AM
Expert Answer
Let us join AC.
In DABC
AB < BC (AB is smallest side of quadrilateral ABCD)
2 < 1 (angle opposite to smaller side is smaller) ... (1)
In DADC
AD < CD (CD is the largest side of quadrilateral ABCD)
4 < 3 (angle opposite to smaller side is smaller) ...(2)
On adding equations (1) and (2), we have
2 + 4 < 1 + 3
C < A
A > C
Let us join BD.
In DABD
AB < AD (AB is smallest side of quadrilateral ABCD)
8 < 5 (angle opposite to smaller side is smaller) ... (3)
In DBDC
BC < CD (CD is the largest side of quadrilateral ABCD)
7 < 6 (angle opposite to smaller side is smaller) ... (4)
On adding equations (3) and (4), we have
8 + 7 < 5 + 6
D < B
B > D
Answered by | 11 Aug, 2017, 11:09: AM
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