In fig shown ,the system is released from rest.Find the velocity of block A when block B has fallen a distance l.Assume all pulleys to be massless and frictionless.
Asked by m.nilu
21st August 2018,
2:48 PM
Answered by Expert
Answer:
Figure shows the Tension forces acting on the chords of pulleys at various points.
When the system is released, block-A is getting an accleleration a given by,
a = (2T-mg)/m = mg/m = g
when block B has fallen a length l, due to length constraints, block-A will move a distance 2l upwards.
velocity v of block-A after travelling a distance 2l, starting from rest, is calculated from, v2 = 2×g×2l , or v = 
Answered by Expert
28th August 2018,
3:26 PM
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