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CBSE Class 9 Answered

In fig., ABC and DBC are two isosceles triangles on the same base BC and the vertices A and D are on the same side of BC. AD is extended to meet BC at P. Prove that AP bisects A. .
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer

Given: Two isosceles triangles ABC and DBC.

To Prove: AP bisects A.

Proof:

In ABD and ACD

AB = AC (given)

BD = CD (given)

AD = AD (common)

So by CPCTBAD = CAD

AP bisects BAC.

Answered by | 04 Jun, 2014, 03:23: PM
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