CBSE Class 9 Answered
In
fig., ABC and DBC are two isosceles triangles on the same base BC
and the vertices A and D are on the same side of BC. AD is extended to meet
BC at P. Prove that AP bisects A.
.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Given: Two isosceles triangles ABC and DBC.
To Prove: AP bisects A.
Proof:
In ABD and ACD
AB = AC (given)
BD = CD (given)
AD = AD (common)
So by CPCTBAD = CAD
AP bisects BAC.
Answered by | 04 Jun, 2014, 03:23: PM
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