In analogy to O2+[PtF6]− a compound N2+[PtF6]− will not be formed because
the I⋅E of N2gas higher than that of O2 gas.
why not the I⋅E of N gas higher than that of O gas.?
Asked by imtiyazmulla68
9th April 2018,
10:52 PM
Answered by Expert
Answer:
The I.E. of N2 gas is higher than that of O2 .
The I.E. is decreasing from left to right in the periodic table hence the N2 cannot lose its electrons so easily as O2 in forming O2+[PtF6]−.
That's why compound N2+[PtF6]− .
Answered by Expert
10th April 2018,
10:21 AM
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