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In an atom, which has 2K, 8L,18M and 2N electrons in the ground state. The total number of electrons having magnetic quantum number, m = 0 is
Asked by kumarisakshi0209 | 22 Mar, 2019, 11:49: AM
answered-by-expert Expert Answer
We have given, 2K, 8L,18M and 2N electrons in the ground state which means,
 
2K    = 1s2
8L    = 2s2  2p6
18M = 3s2  3p6 3d10
2N   = 4s2  
 
For, s, p and d, m=0 with spins +1/2 i.e., 2 electrons
 
Hence find electrons for each orbital,
 
2K    = 1s2                      =  2 electrons
8L    = 2s2  2p6             =  4 electrons
18M = 3s2  3p6 3d10   =  6 electrons
2N   = 4s2                =  2 electrons
                     Total   = 14 electrons
 
 
The total number of electrons having magnetic quantum number, m = 0 is 14
Answered by Ramandeep | 22 Mar, 2019, 05:41: PM
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