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CBSE Class 9 Answered

In ΔABC, AB = AC, A = 36°. If the internal bisector of C meet AB at D, prove that AD = BC.
Asked by Topperlearning User | 06 Dec, 2013, 10:43: AM
answered-by-expert Expert Answer

 

AB = AC

C = B [angles opposite to equal sides are equal]

In ABC A + B + C = 180o [Angle sum property of ]

36o   + 2C = 180o

2C = 144o

C = 72o

DCA =

DCA = DAC = 36o

AD = CD [sides opposite to equal angles are equal] … (i)

In CDB

AB C + C + CDB = 180o

72o + 36o + CDB = 180o

CDB = 180o - 72o - 36o

CDB = 72o

CDB = DBC = 72o

BC = CD [sides opposite to equal angles are equal] … (ii)

AD = BC (Using (i) and (ii))

Answered by | 06 Dec, 2013, 12:43: PM
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