CBSE Class 9 Answered
In ΔABC, AB = AC, A = 36°. If the internal bisector of C meet AB at D, prove that AD = BC.
Asked by Topperlearning User | 06 Dec, 2013, 10:43: AM
Expert Answer
AB = AC
C = B [angles opposite to equal sides are equal]
In ABC A + B + C = 180o [Angle sum property of ]
36o + 2C = 180o
2C = 144o
C = 72o
DCA =
DCA = DAC = 36o
AD = CD [sides opposite to equal angles are equal] … (i)
In CDB
AB C + C + CDB = 180o
72o + 36o + CDB = 180o
CDB = 180o - 72o - 36o
CDB = 72o
CDB = DBC = 72o
BC = CD [sides opposite to equal angles are equal] … (ii)
AD = BC (Using (i) and (ii))
Answered by | 06 Dec, 2013, 12:43: PM
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