CBSE Class 9 Answered
In a triangle, ABC, AC is greater than AB and AD is the bisector of angle A, show that ADC is greater than ADB
Asked by anuradha.rajesh | 06 Nov, 2018, 05:57: PM
Expert Answer
AC>AB and AD is bisector of angle A
⇒angleBAD = angle CAD = Angle A/2
Also in triangle ABD
angle ADB = 180-angle ABD + Angle A/2
Now, angle ABD> angle ACD ...(∵ angle opposite to longer side is greater)
Now, angle ABD> angle ACD ...(∵ angle opposite to longer side is greater)
⇒angle ABD +angle A/2 > angle ACD + angle A/2
⇒180-angle ACD + angle A/2 > 180-angle ABD +angle A/2
⇒angle ADC > angle ADB
Answered by Arun | 13 Nov, 2018, 10:31: AM
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