ICSE Class 10 Answered
In a triangle ABC, AB = 6, BC = 8 and AC = 10. A perpendicular from B meets the side AC at D. A circle is drawn with radius BD and centre B. If the circle cuts AB and BC respectively at P and Q, then AP : QC is equal to
Asked by keshavendu35 | 23 Aug, 2018, 10:47: PM
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Answered by Sneha shidid | 24 Aug, 2018, 11:18: AM
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