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In a reversible reaction 2NO2<--K1—K2---->N2O4, the rate of disappearance of NO2 is equal to:(K1 is rate of forward reaction, K2 rate of backward reaction.) 1) 2K1[NO2]2/K2 2) 2K1[NO2]2-2K2[N2O4] 3) 2K1[NO2]2-K2[N2O4] 4) 2(K1-K2)[NO2]
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Asked by koushikr063 | 06 May, 2019, 10:37: AM
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R a t e space o f space f o r w a r d space r e a c t i o n comma space R subscript f space equals space K subscript 1 left square bracket N O subscript 2 right square bracket squared space equals space minus 1 half fraction numerator d left square bracket N O subscript 2 right square bracket over denominator d t end fraction R a t e space o f space b a c k w a r d space r e a c t i o n comma space R subscript b space equals space K subscript 2 left square bracket N subscript 2 O subscript 4 right square bracket S o comma space r a t e space o f space d i s a p e a r a n c e space o f space N O subscript 2 space semicolon space fraction numerator negative d left square bracket N O subscript 2 right square bracket over denominator d t end fraction space equals space 2 K subscript 1 left square bracket N O subscript 2 right square bracket to the power of 2 space end exponent minus space K subscript 2 left square bracket N subscript 2 O subscript 4 right square bracket space space space space space space space space space space space space space space space space left curly bracket S u b t r a c t e d space b e c a u s e space t h e space o t h e r space r e a c t i o n space i s space r e v e r s e space t o space f i r s t space o n e right curly bracket h e n c e space c o r r e c t space o p t i o n space i s space c. space left curly bracket space s e c o n d space e q u a t i o n space w a s space n o t space m u l t i p l i e d space b y space 2 space sin c e space i t s space s t o i c h i o m e t r i c space c o e f f i c i e n t space i s space 1 right curly bracket
Answered by Sumit Chakrapani | 06 May, 2019, 11:21: AM

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