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In a NaCl type crystal distance between Na+ and Cl- ion is 2.814 A and the density of solid is 2.167 g cm-3 then find out yhe value of Avogadro's constant.
Asked by harinderamit1234 | 02 Jan, 2020, 01:23: AM
answered-by-expert Expert Answer
Given:
 
Z for NaCl = 4
 
Density = 2.167 g cm-3  
 
Molar mass of NaCl = 58.5
 
NaCl: FCC structure = 2(rNa + RCl) = a
 
a = 2.814 × 2
 
a =5.682 Å
 
We know,
 
1 Angstrom = 100 pm
 
1 pm = 10−10 cm
 
a =568.2 pm
 
a =568.2 × 10−10 cm
 
We have,
 
Density 
 
space space equals fraction numerator straight n cross times straight m over denominator straight a cubed space cross times space straight N subscript straight A end fraction straight N subscript straight A space equals space fraction numerator straight n cross times straight m over denominator straight a cubed space cross times space straight d end fraction space space space space space equals fraction numerator 4 cross times 58.5 over denominator open parentheses 568.2 cross times 10 to the power of negative 10 end exponent close parentheses cubed space cross times space 2.167 end fraction straight N subscript straight A space equals space fraction numerator 234 over denominator open parentheses 568.2 cross times 10 to the power of negative 10 end exponent close parentheses cubed space cross times space 2.167 end fraction straight N subscript straight A space equals space 5.99 space cross times 10 to the power of 23 space straight N subscript straight A space almost equal to space 6 space cross times 10 to the power of 23 space
 
Avogadro's constant = 6.0 × 1023 
Answered by Varsha | 02 Jan, 2020, 01:11: PM

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In a NaCl type crystal distance between Na+ and Cl- ion is 2.814 A and the density of solid is 2.167 g cm-3 then find out yhe value of Avogadro's constant.
Asked by harinderamit1234 | 02 Jan, 2020, 01:23: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
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