CBSE Class 12-science Answered
In a hostel , 60% of the students read hindi newspaper , 40% read English newspaper and 20% read both hindi and English newspaper . A student is selected at random
Find the probability that he reads neither hindi nor English newspaper
Asked by haroonrashidgkp | 04 Nov, 2018, 08:27: PM
Expert Answer
Let A be the probability that students who read Hindi newspaper and B be the probability of stduents who reads English newspapers.
P(A) = 60%, P(B) = 40% and P(A ∩ B) = 20%
To find the probability of students reads neither Hindi nor English newspapers first we find
P(A 
B) = P(A) + P(B) - P(A ∩ B)
B) = P(A) + P(B) - P(A ∩ B) = 60% + 40% - 20% = 80%
Required probability = P(A' ∩ B') = 1 - P(A B) = 20% = 1/5
B) = 20% = 1/5
Answered by Sneha shidid | 06 Nov, 2018, 11:55: AM
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