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CBSE Class 9 Answered

In a circular park of radius 25 m,three girls Neha,Preeti and rashmi are sitting at equal distance on it's boundary each having a cell phone and talking to each other.Find the distance Neha and reshma
Asked by somendra_nath | 16 Feb, 2016, 09:30: PM
answered-by-expert Expert Answer
In space the space given space figure space straight P comma space straight N space and space straight R space represents space the space position space of space the space Preeti comma space Neha space and space Rashmi. Join space points space straight P comma space straight N space and space straight R. Let space straight O space be space the space centre space of space the space circle. Draw space OM space perpendicular NR space Points space straight P comma space straight N space and space straight R space are space are space equidistant space from space each space other space so space increment PNR space is space an space equilateral space triangle. rightwards double arrow angle straight P space equals space 60 degree angle NOR space equals space 2 angle straight P space equals space 120 degree space space left square bracket Central space angle space theorem. right square bracket space In space increment NOR space comma ON space equals space OR space left square bracket Radii space of space the space circle right square bracket rightwards double arrow angle ONR space equals angle ORN angle NOR space plus angle ORN space plus space angle ONR space equals 180 degree 2 angle ORN space plus 120 degree space equals space 180 degree angle ORN space equals space 30 degree space In space increment NOR space angle ORN space plus space angle OMR space plus space angle RON space equals 180 degree 30 degree space plus space 90 degree plus space angle RON space equals 180 degree angle RON space equals 60 degree So space increment NOR space space is space 30 degree minus 60 degree minus 90 degree space triangle. Side space opposite space to space 60 degree space is space fraction numerator square root of 3 over denominator 2 end fraction times space of space the space hypotaneous. MR space equals space fraction numerator square root of 3 over denominator 2 end fraction cross times OR space equals fraction numerator square root of 3 over denominator 2 end fraction cross times 25 space equals fraction numerator 25 square root of 3 over denominator 2 end fraction straight m By space construction space OM space perpendicular NR We space know space that space perpendicular space drawn space from space the space centre space of space the space circle space bisects space the space chord. So space NM space equals space MR NR space equals space 2 MR space equals 25 square root of 3 cm Distance space between space Neha space and space reshma space is space 25 square root of 3 cm.
Answered by Vijaykumar Wani | 17 Feb, 2016, 11:33: AM

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CBSE 9 - Maths
prove that of all chords of circle through a given point within it, the chord which is bisected at that point is the smallest
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CBSE 9 - Maths
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CBSE 9 - Maths
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CBSE 9 - Maths
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CBSE 9 - Maths
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CBSE 9 - Maths
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CBSE 9 - Maths
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CBSE 9 - Maths
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CBSE 9 - Maths
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CBSE 9 - Maths
begin mathsize 12px style Two space chords space AB space and space AC space of space straight a space circle space are space equal. space Prove space that space the space centre space of space the space circle space lies space on space the space angl e space bisector space of space angle BAC. end style
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