ifa piece of iron gains 10 percent of its weight due to partial rusting into fe2o3 then what is the percentage of total iron rusted
The chemical reaction for rusting of iron is as follows:
4Fe + 3O2 → 2Fe2O3
Initial mass of iron =100 gm
Mass of Fe2O3 = 110 gm
Mass of oxide = 10 gm
Now, from equation,
To form 2 moles of rust it requires 3 moles of O2 requires 4 moles of Fe
Mass of Fe reacted = 0.4166×56
=23.33%
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