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if y1, y2, y3 be the ordinates of vertices of the triangle inscribe in a parabola y2=4ax, then show that the area of the triangle is 1/8a|(y1-y2)(y2-y3)(y3-y1)|

Asked by 2nd March 2013, 10:27 PM
Answered by Expert
Answer:
 = 1/8a |(2at1 - 2at2)(2at2 - 2at3)(2at3 - 2at1)|
 = 1/8a|(y1 - y2)(y2 - y3)(y- y1)| 
Answered by Expert 2nd March 2013, 11:36 PM
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