CBSE Class 9 Answered
if x=2y+6 then find the value of xcube-8ycube-36xy-216
Asked by nilangi | 22 Sep, 2013, 09:47: AM
Expert Answer
Given: x=2y+6
x-2y-6=0 ----------------- (1)
x3- 8y3- 216 - 36xy
= (x)3+ (-2y)3+ (-6)3 - 3*x*(-2y)*(-6)
=(x-2y-6) (x2+4y2+36+2xy-12y+6x)
= 0 (x2+4y2+36+2xy-12y+6x) (from equation (1) )
=0
Answered by | 22 Sep, 2013, 02:39: PM
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