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ICSE Class 9 Answered

If x = 1-square root of 2 , find the value of open parentheses x minus bevelled 1 over x close parentheses to the power of 4open parentheses bevelled fraction numerator x minus 1 over denominator x end fraction close parentheses to the power of 4
Asked by singadityah7 | 20 Jun, 2019, 10:50: AM
answered-by-expert Expert Answer
x = 1 - √2 
begin mathsize 16px style 1 over straight x equals fraction numerator 1 over denominator 1 minus square root of 2 end fraction
fraction numerator begin display style 1 end style over denominator begin display style straight x end style end fraction equals fraction numerator begin display style 1 end style over denominator begin display style 1 minus square root of 2 end style end fraction cross times fraction numerator 1 plus square root of 2 over denominator 1 plus square root of 2 end fraction
fraction numerator begin display style 1 end style over denominator begin display style straight x end style end fraction equals fraction numerator begin display style 1 plus square root of 2 end style over denominator begin display style 1 minus 2 end style end fraction
fraction numerator begin display style 1 end style over denominator begin display style straight x end style end fraction equals negative open parentheses 1 plus square root of 2 close parentheses end style
x - 1/x = 2
(x - 1/x)4(x - 1/x)4 
= (x - 1/x)8
= 28 
= 256
Answered by Sneha shidid | 20 Jun, 2019, 12:21: PM
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