CBSE Class 11-science Answered
If three lines whose equations are y = mx + a, y = nx + b and y = px + c are concurrent, then show that m (b - c) + n (c - a) + p (a - b) = 0.
Asked by Topperlearning User | 29 Apr, 2014, 01:05: PM
Expert Answer
The equations of lines are
y = mx + a --- (i)
y = nx + b --- (ii)
And y = px + c --- (iii)
Subtracting equation (i) from (ii),
0 = (m - n)x + a - b
x =
Putting the values of x and y in third equation,
Answered by | 29 Apr, 2014, 03:05: PM
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