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If there are 999 bases in an RNA that codes for a protein with 333 ammino acids,  and the base at position 901 is deleted such that the lenght of RNA becomes 998 bases,  how many codons will be altered? 
1) - 1
2) - 33
3) - 11
4) - 333

Asked by ay91555 12th July 2017, 11:57 AM
Answered by Expert
Answer:

As per the given problem, there are 999 bases in the RNA that code for 333 amino acids.

We know that 1 codon consists of three bases, usually corresponding to a single amino acid.

This implies that there are 333 codons which code for 333 amino acids.

Now, out of 999 bases, if the base at position 901 is deleted, then the remaining 98 bases corresponding to 33 codons of amino acids will be altered because deletion of base at 901 position causes a frame shift mutation in the remaining 33 codons.

Answered by Expert 12th July 2017, 12:18 PM
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