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 If the two slits in Young's double slit experiment have width ratio 4:1, deduce the ratio of the intensity of maxima and minima in the interference pattern?
PLEASE EXPLAIN THE ANSWER
 

Asked by modi72879 14th October 2017, 1:18 PM
Answered by Expert
Answer:
begin mathsize 12px style
Width space is space directly space proportional space to space the space intensity
And space intensity space is space directly space proportional space to space square space of space amplitude
Maximum space Intensity space the space square space of space sum space of space both space amplitude space space and space
minimum space intensity space will space be space square space of space the space subtraction space of space both space amplitude.
straight w subscript 1 over straight w subscript 2 equals straight I subscript 1 over straight I subscript 2 equals straight A squared over straight B squared
4 over 1 equals straight A squared over straight B squared
straight A over straight B equals 2 over 1 semicolon space straight A equals 2 xB

straight I subscript max over straight I subscript mini equals fraction numerator left parenthesis straight A plus straight B right parenthesis squared over denominator left parenthesis straight A minus straight B right parenthesis squared end fraction equals fraction numerator left parenthesis 2 straight B plus straight B right parenthesis squared over denominator left parenthesis 2 straight B minus straight B right parenthesis squared end fraction equals open parentheses fraction numerator begin display style 3 straight B end style over denominator begin display style straight B end style end fraction close parentheses squared equals 9 over 1 end style
Answered by Expert 4th December 2017, 11:24 AM
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