CBSE Class 10 Answered
If the roots of the equation (b-c)x^2 + (c-a)x + (a-b)=0 are equal,then prove that 2b=a+c
Asked by | 29 Jan, 2014, 05:02: PM
Expert Answer
For equal roots, discriminant should be 0.
So, (c-a)² - 4(b-c)(a-b)= 0
c² - 2ac + a² - 4ab + 4b² + 4ac - 4bc = 0
c² + 2ac + a² + 4b² - 4ab - 4bc = 0
(c + a)² + 4b² - 4b(a + c) = 0
[(a + c) - (2b)]² = 0
Hence, 2b = a + c
Answered by | 29 Jan, 2014, 05:39: PM
Application Videos
Concept Videos
CBSE 10 - Maths
Asked by pathakvaishnavi9139 | 23 Mar, 2024, 10:45: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by mustafahssn786 | 23 Mar, 2024, 06:25: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by choudharyniki001 | 22 Mar, 2024, 08:49: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by jagdishdabang79 | 18 Mar, 2024, 08:40: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by vn3950372 | 18 Mar, 2024, 08:38: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by vestigevestige85 | 17 Mar, 2024, 09:44: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by jayashreelatha04 | 17 Mar, 2024, 05:38: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by suvarnaapkare | 15 Mar, 2024, 04:59: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by anubhutiupadhaya | 15 Mar, 2024, 03:33: PM
ANSWERED BY EXPERT