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CBSE - X - Mathematics - Polynomials

if the polynomial p(x) is devided by x^2 + 4x + 2, then the quotient polynomial x^@ - 4x + 14 and the remainder polynomial 9x-13 are obtained. find polynomial p(x)

Asked by 21st July 2012, 6:53 PM
Answered by Expert

Answer:

Answer : Given : if the polynomial p(x) is devided by x^2 + 4x + 2, then the quotient polynomial x^@ - 4x + 14 and the remainder polynomial 9x-13 are obtained
To find p(x)
 
Dividend = p(x)
divisor :  x2 + 4x + 2
quotient: x2 - 4x + 14
remainder 9x-13 
 
we know , 
Dividend = divisor * quotient + remainder  
=> p(x) = ( ( x2 + 4x + 2 ) * ( x2 - 4x + 14 ) ) + ( 9x-13)
=> p(x) = ( x4 + 48x + 28 ) + ( 9x-13)
=> p(x) = (x4 + 57x + 15 ) Answer 
Answered by Expert 21st July 2012, 11:36 PM

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