if the earth is at one fourth of its present distance from the sun the duration of the year would be
Asked by vvelesha
2nd October 2018,
2:16 PM
Answered by Expert
Answer:
Gravitational force of attraction provides the centripetal force to the earth to revolve around the sun.
Assuming circular orbit, we write
where G is gravitational constant, M is mass of sun, m is mass of earth, R is radius of orbit and ω is angular speed.
If T is period of revolution, then
ω = 2π/T .........(2)
substituting for ω from eqn.(2) in eqn.(1), we get 
By considering all constants, we write 
...........................(4)
...........................(4)Let T ' be the time period of revolution if orbital radius is reduced to (1/4)th of its original value, then we have
if we consider normal duration of year as 365 days, then 
Answered by Expert
3rd October 2018,
4:47 AM
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