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CBSE Class 11-science Answered

if position 'x' defined a function of time as: x(t)=t*3+2t*2+3t+4 . (1) find initial position of particle (2) find velocity in time interval from to =0 at t=3 second
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Asked by ad4957216 | 03 Jan, 2023, 04:54: PM
answered-by-expert Expert Answer
Position x(t) = t3 + 2 t2 + 3 t + 4
 
initial position x(0) is determined from above equation by substituting t = 0
 
x(0) = 4 m
 
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velocity function is determined by differentiating above equation
 
v(t) = dx/dt =  3 t2 + 4 t + 3
 
initial velocity at t = 0 , v(0) = 3 m/s
 
velocity at time t = 3 , v(3) = 3(9) +4(3) + 3 = 42 m/s
Answered by Thiyagarajan K | 03 Jan, 2023, 05:07: PM
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