If p(x,y) is a point equidistant from the points A(6,-1) and B(2,3) show that x-y=3
Asked by lindatariang610
11th August 2021,
8:16 AM
Answered by Expert
Answer:
Given: A(6, -1) and B(2,3) are equidistant from the point P(x, y)
Then, PA = PB
PA2 = PB2
(x - 6)2 + (y + 1)2 = (x - 2)2 + (y - 3)2
x2 + 36 - 12x + y2 + 1 + 2y = x2 + 4 - 4x + y2 + 9 - 6y
-12x + 2y + 24 = -4x - 6y
-8x + 8y = -24
x - y = 3
Answered by Expert
11th August 2021,
12:53 PM
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